(3x+4)(x^2-3x-4)=

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Solution for (3x+4)(x^2-3x-4)= equation: 


Simplifying
(3x + 4)(x2 + -3x + -4) = 0

Reorder the terms:
(4 + 3x)(x2 + -3x + -4) = 0

Reorder the terms:
(4 + 3x)(-4 + -3x + x2) = 0

Multiply (4 + 3x) * (-4 + -3x + x2)
(4(-4 + -3x + x2) + 3x * (-4 + -3x + x2)) = 0
((-4 * 4 + -3x * 4 + x2 * 4) + 3x * (-4 + -3x + x2)) = 0
((-16 + -12x + 4x2) + 3x * (-4 + -3x + x2)) = 0
(-16 + -12x + 4x2 + (-4 * 3x + -3x * 3x + x2 * 3x)) = 0
(-16 + -12x + 4x2 + (-12x + -9x2 + 3x3)) = 0

Reorder the terms:
(-16 + -12x + -12x + 4x2 + -9x2 + 3x3) = 0

Combine like terms: -12x + -12x = -24x
(-16 + -24x + 4x2 + -9x2 + 3x3) = 0

Combine like terms: 4x2 + -9x2 = -5x2
(-16 + -24x + -5x2 + 3x3) = 0

Solving
-16 + -24x + -5x2 + 3x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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